Question

an Athlete starting from rest picks up a velocity of 10m/s over a distance of 100m . calculate 1.the acceleration generated by the athlete, and 2. the time in which he completes the race​

Answer 1

Answer:

Explanation:

Given,

Initial velocity, u = 0 m/s (As it starts from rest)

Final velocity, v = 10 m/s

Distance covered, s = 100 m

To Find,

1. Acceleration, a = ?

2. Time taken, t = ?

Formula to be used,

3rd equation of motion,

v² - u² = 2as

1st equation of motion,

v = u + at

Solution,

1. Acceleration, a,

Putting all the values, we get

v² - u² = 2as

⇒ (10)² - (0)² = 2 × a × 100

⇒ 100 = 200s

⇒ a = 100/200

⇒ a = 1/2

⇒ a = 0.5 m/s²

Hence, the acceleration of the athlete is 0.5 m/s².

Now, the 2. time taken, t,

v = u + at

⇒ 10 = 0 + 0.5 × t

⇒ 10 = 0.5t

⇒ t = 10/0.5

⇒ t = 20 seconds

Hence, the time taken to complete the race is 20 seconds.

Answer 2

Answer:-

• Acceleration is 0.5m/s²
• Time taken is 20 second.

Solution:-

• Initial Velocity ,u = 0m/s
• Final Velocity ,v = 10m/s
• Distance travelled ,s = 100 m

As we know that Acceleration is defined as the rate of change of velocity at per unit time.

Using 3rd Equation of Motion

•• v² = u² +2as

Substitute the value we get

→ 10² = 0² + 2×a × 100

→ 100 = 0 + 200×a

→ 100 = 200×a

→ a = 100/200

→ a = 1/2

→ a = 0.5m/s²

• Hence, the acceleration of the athlete is 0.5 m/s².

Now, Calculating the time taken by athlete to complete the race .

Using First Equation of Motion

• v = u +at

Substitute the value we get

→ 10 = 0 + 0.5×t

→ 10 = 0.5×t

→ t = 10/0.5

→ t = 100/5

→ t = 20 s

• Hence, the time taken by the athlete to complete the race is 20 second.