Question

An Athlete starting from rest picks up a velocity of 10m/s over a distance of 100m . calculate 1.the acceleration generated by the athlete, and 2. the time in which he completes the race​

Answer 1

Here, as per the provided question we are asked to find the time when he complete the race ·—

GIVEN :

• Final Velocity = 10m/s
• Distance Travelled = 100m
• Initial Velocity = 0m/s

TO FIND :

• The time taken by an athelete to cover / Complete the distance of the race = ?

STEP-BY-STEP EXPLANATION :

Now, we are asked to find the time taken by an athelete to cover the distance of the race ·–

→ Using a specific formula :

• v² = u^2 + 2as

[ Substituting the values ]

→ v² = u² + 2as

→ 10² = 0² + 2 × a × 100

→ 100 = 0 + 200a

→ 100 = 200 × a

→ a = 100/200

→ a = 0.5m/s²

→ Acceleration = 0.5m/s^2

Distance covered (period) = ?

→ v = u + at

→ 10 = 0 + 0.5 × t

→ t = 10/0.5

→ t = 100/5 = 20

→ t = 20s

hence, the time taken to finish the race = 20s✔️.

Answer 2

Explanation:

GIVEN THAT

• An Athlete starting from rest picks up a velocity of 10m/s over a distance of 100m.

so

initial velocity(u) = 0 m/s

final velocity (v) = 10m/s

distance travel = 100 m

• second Equation of motion =

${v}^{2} = {u}^{2} + 2as$

Where,

v = Final Velocity

u = Initial Velocity

a = Acceleration

s = Travel Distance

Now putting the value in Equation .

${v}^{2} = {u}^{2} + 2as \\ = > {10}^{2} = {0}^{2} + 2 \times a \times 100 \\ = > 200a = 100 \\ = > a = \frac{100}{200} \\ = > a = 0.5 \: m {s}^{ - 2}$

Now the first Equation of motion

$v = u + at$

where,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Take time

Now the putting value in this equation

$v = u + at \\ = > 10 = 0 + 0.5t \\ = > t = \frac{10}{0.5} \\ = > t = 20sec$

Hence We got

Acceleration of Athlete = 0.5 m per sec sq

Take time = 20 sec