Question

an athlete takes 2seconds to reach his maximum speed of 18km/h.what is the magnitude of his average acceleration

Answer 1

Hey User
Answer will be 2.5m/s²
as initially the athlete was at rest i.e u = 0
finally v = 18km/hr = 5 m/s
hence by First Equation of Motion a = v-u/t
a =5-0/2 m/s² i.e 2.5m/s²
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Answer 2

convert speed in site unit
18x5/18 =5m/s
avg.acc. =max.speed/time taken
=5/2
=2.5