Question

An athlete throws a ball with a velocity of 15 m/s at an angle of 30° with the horizontal. If the point of reference is 2 meters above the ground, what is the distance of the throw?

Answer 1

Answer:

Explanation:

GIVEN VELOCITY=30

RESOLVING IT WE GET V COS 30(HORIZONTAL),V SIN 30(VERTICALLY)

NOW HORIZONTAL RANGE OR DISTANCE=V^2 SIN2X/G

                                                                         =(V COS 30)^2*SIN 60/10

                                                                          =(13^2*0.5)/10

                                                                          =8.43 m