Question

An athlete travel distance of 2 km in first hour , 1 km in second hour and 0.5 km in third hour . Calculate the average speed in ( i ) km/hr and ( ii ) m/s​

Answer 1

Explanation:

Time, speed, and distance are related using the equation: Distance = Speed × Time.

Answers: The average speed of the cyclist who travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour is 0.6 km/hr or 1/6 m/s.

To find the average speed we need to use the relation:

Average speed = Total distance traveled/ Total time taken

Let's now consider the conditions given in the question to find the required value.

Explanation:

Let's find the total distance traveled and the total time taken.

The total distance travelled = 1 km + 0.5 km + 0.3 km = 1.8 km.

Total time taken = 1 hr + 1 hr + 1 hr = 3 hr

Now, Average speed = Total distance traveled/ Total time taken

or, Average speed = 1.8/3 = 0.6 km/hr

Now let's convert km/hr to m/sec

Since we know 1 km = 1000 m and 1 hr = (60 × 60) s = 3600 s

Therefore, 1 km/hr = 1000m/3600s

So 0.6 km/hr = 0.6 × 1000/3600 m/s

= (0.6 × 1000)/3600 m/s

= 600/3600 m/s

= 1/6 m/s

Therefore, the avergae speed of the cyclist is 0.6 km/hr or 1/6 m/s.

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Answer 2

Distance in one hour = 2 km

Distance in second hour = 1 km

Distance in third hour = 0.5 km

We know that,

Average speed = total distance /total time

i) Average speed in km/hr

ν = D/T

= 1.17km/hr

ii) Average speed in m/s

ν = 1.17* 5/8

= 0.73m/s

The average velocity is 1.17 km/hr and 0.73 m/s.