Question

An athlete weighing 50 kg has 100 J of K.E. Calculate his speed.

Answer 1

Answer:

Formula for kinetic energy is

$1 \div 2(m {v}^{2} )$

m=50

thus placing the value we get

1/2(50×v^2) =100

v^2=(2×100) /50

v^2= 4

v=√4

v=2

thus the speed is 2m/s

hope this will help!

thanku

Answer 2

Answer:

This is the Physics Question,

Important Formula:

$k.e. \: = \: \frac{1}{2} \: m \times v^{2}$

Given:

m = mass = 50 kg

K.E = 100J

To Find:

speed = ?

Substitute the values in the Formula:

∴ 100 = 1/2 50 × v²

∴ 100/50 = 1/2 v²

∴ 1/2 v² = 2

∴ v² = 2×2

$<strong>∴</strong><strong> </strong><strong>v</strong><strong> </strong><strong>=</strong><strong> </strong><strong>speed</strong><strong> </strong><strong>=</strong><strong> </strong><strong> </strong><strong>√</strong><strong>4</strong><strong> </strong><strong>=</strong><strong> </strong><strong>2</strong>$