An athletic completes one round of a circular track of diameter 200m in 40 s. what will be the distance covered and the displacement at the end of 2 minutes 20 s?
Answers
Answer:
Distance - 2200 m
Displacement - 200m
Explanation:
Circumference of the track = 2πr
Here r = 200/2 = 100
So, Circumference = 4400/7
4400/7 m is covered in 40 s
So, In 140 s, Distance = (4400/7) × 3.5 [ 3.5 because the time taken is 120 + 20, i.e, 3.5 × 40 ]
so, Distance = 2200 m
Displacement = Shortest path = 200 m [ Distance on last 20 seconds. 200 m because required distance is the diameter... as in 20 s, half of the circle is covered ]
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Answer:
radius = 100
circumference = 2×22/7×100
2×22/7×100 meter in 40 s
therefore in 2 minutes 20 second
distance=2×22/7×100×2minutes 20 second/40second
distance =2 × 22/7 ×100 × 140
distance = 88000 meter
NOW DISPLACEMENT
In 140seconds(2 minutes 20seconds)
no. of complete revolutions = 140/40 =3.5(I.e. 3 complete revolutions and one half revolution)
therefore current position of athlete
=half of the circle
now displacement =diameter
=200m
Explanation:
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