Question

an athletic track 14 metre wide consists of two straight sections 120 M long joining semicircular ends whose inner radius is 35 M calculate the area of the athletic track

Answer 1

l = 120m, b = 14m, r1 = 35m, r2 = 49m

area of 2 straight sections = 2*l*b = 2*120*14 = 3360m²
area of 2 semicircular ends = 2[(½πr2²)-(½πr1²)]
= 2*½*22/7*(49²-35²)
= 22(2401-1225)/7
= 22*1176/7
= 22*168
= 3696

total area = 3696+3360 = 7056m²

Answer 2

Answer:

Step-by-step explanation:

area of 2 straight sections = 2*l*b = 2*120*14 = 3360m²

area of 2 semicircular ends = 2[(½πr2²)-(½πr1²)]

= 2*½*22/7*(49²-35²)

= 22(2401-1225)/7

= 22*1176/7

= 22*168

= 3696

total area = 3696+3360 = 7056m²