an athletic track 14 metre wide consists of two straight sections 120 M long joining semicircular ends whose inner radius is 35 M calculate the area of the athletic track
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Answered by
158
l = 120m, b = 14m, r1 = 35m, r2 = 49m
area of 2 straight sections = 2*l*b = 2*120*14 = 3360m²
area of 2 semicircular ends = 2[(½πr2²)-(½πr1²)]
= 2*½*22/7*(49²-35²)
= 22(2401-1225)/7
= 22*1176/7
= 22*168
= 3696
total area = 3696+3360 = 7056m²
area of 2 straight sections = 2*l*b = 2*120*14 = 3360m²
area of 2 semicircular ends = 2[(½πr2²)-(½πr1²)]
= 2*½*22/7*(49²-35²)
= 22(2401-1225)/7
= 22*1176/7
= 22*168
= 3696
total area = 3696+3360 = 7056m²
Answered by
27
Answer:
Step-by-step explanation:
area of 2 straight sections = 2*l*b = 2*120*14 = 3360m²
area of 2 semicircular ends = 2[(½πr2²)-(½πr1²)]
= 2*½*22/7*(49²-35²)
= 22(2401-1225)/7
= 22*1176/7
= 22*168
= 3696
total area = 3696+3360 = 7056m²
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