Physics, asked by luvkumar2492, 11 months ago

An atlethe starting from a rest picks ups a velocity of 10 m/s over a distance of 100m . Calcutale (i) the acceralation generated by the athlete and (ii) the time in which complates the race

Answers

Answered by Anonymous
4

Answer:-

a = 0.5 m/s²

t = 20 s

Given :-

u = 0 m/s

v = 10 m/s

s = 100 m

To find :-

The acceleration generated by athlete and time taken to complete the race.

Solution :-

Let it takes time t to complete the race.

By using 2 nd equation of motion we can find its acceleration.

 2as = v^2 - u^2

 2 \times a \times 100 = (10) ^2 - (0) ^2

 200 \times a = 100

 a = \dfrac{100}{200}

 a = 0.5 m/s^2

Now, we have to find time t.

a = 0.2 m/s²

v = 10 m/s

u = 0 m/s

Time take to complete the race = [/tex] v = u + at [/tex]

 10 = 0 + 0.5 \times t

 10 = \dfrac{5t}{10}

 5t = 100

 t = \dfrac{100}{5}

 t = 20 s

hence,

Acceleration generated by athlete is 0.5 m/s².

Acceleration generated by athlete is 0.5 m/s².And time taken to complete the race will be 20 s.

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