Question

An atmospheric chemist reports that one dm3 of air in an urban area contained 3.5×10 raise to part -4 what was the concentration of CO in ppm​

Answer 1

Answer:

we suppose that ppm are cm^3/m^3, we can calculate oxygen concentration as:

V(O2)/V(total) = (209.5+x)cm^3/10^-3m^3.

b) If ppm = mg/l:

m(O2)/V(total) = (209.5+x)*32/(Vm*1).

Here x= is volume of oxygen added, x(cm^3)=1*t ((cm^3/min)*min), t(min) is time during which oxygen was added, 32 is molar mass of O2, Vm is molar volume, 1 = 1litre, volume of your chamber.

The 3rd way of calculations :

xA = mA / mtotal

Parts Per Million (ppm) = xA*106

i.e mole fraction of component (XA *106 )