An atom crysatllize in fcc crysatl lattice and has density 10 gcm^-3 with unit cell edge lenght of 100 pm.Calculate no.Of atim present in 1 g of crystal
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density=10 g/cm³
edge length= 100 pm=100×10^-10 cm
mass= 1 g
we know,
density=nM/a³Na
→ 10 =n/(10^-24)(6.023×10²³)
→n=602.3
edge length= 100 pm=100×10^-10 cm
mass= 1 g
we know,
density=nM/a³Na
→ 10 =n/(10^-24)(6.023×10²³)
→n=602.3
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