Question

An atom has a mass of 0.02kg and uncertainty in its velocity is 9.218×10^-6m/s then uncertainty in position is-

Answer 1

This discussion on An atom has a mass of 0.02 kg & uncertainity in its velocity is 9.218 × 10-6m/s then uncertainity in position is (h ...

Answer 2

Answer: 2.86 x 10^-28 m

Explanation:

According to Heisenberg's uncertainty principle,

∆p x ∆x = h/4π where, ∆p = m∆v is the

uncertainty I calculating the

momentum, ∆x is the

uncertainty in calculating the

position and h is the Planck's

constant.

We know, h = 6.63 x 10^-34 J s

So, ∆x = h / (4π x ∆p)

= (6.63 x 10^-34) / (4x3.14 x

0.02x9.218x10^-6)

= 2.86 x 10^-28 m