An atom of an element has one electron in the valence shell and the two consecutive
inner shells have 8 electrons each. Find the atomic number of that element. Write the
electronic configuration of preceding and succeeding elements.
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Answered by
1
Electronic configuration of atom of element which has two electrons in the valence shell and two consecutive inner shells have 8 electrons each is 2,8,8,2. And hence atomic number is element=20
Answered by
2
Answer:
no. of electron in valence shell.=1
no of electrons in two consecutive shell =8
so, 8 +1= 9
the electronic configuration is 1,8
name of element is Flourine
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