An atom of element x weighs 6.64 × 10^-23 . Calculate the number of gram atoms in 40 kg of it.
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ASSALAMUALAIKUM
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weight of 1 atom = 6.64×10^-23 g
so, no. of atoms in 40 kg
= 40×10^3 / 6.64×10^-23
= 6.02046 × 10^26 atoms
As, 1 gram atom = no. atoms in one mole = 6.02×10^23 (avagadro number)
so, no. of gram atom
= 6.02046×10^26/6.02×10^23
=1000 gram atoms
INSHAALLAH it will help you!
☺❤☺
weight of 1 atom = 6.64×10^-23 g
so, no. of atoms in 40 kg
= 40×10^3 / 6.64×10^-23
= 6.02046 × 10^26 atoms
As, 1 gram atom = no. atoms in one mole = 6.02×10^23 (avagadro number)
so, no. of gram atom
= 6.02046×10^26/6.02×10^23
=1000 gram atoms
INSHAALLAH it will help you!
Answered by
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heya...!!!
Answer:
weight of 1 atom = 6.64×10^-23 g
so, no. of atoms in 40 kg
= 40×10^3 / 6.64×10^-23
= 6.02046 × 10^26 atoms
As, 1 gram atom = no. atoms in one mole = 6.02×10^23 (avagadro number)
so, no. of gram atom
= 6.02046×10^26/6.02×10^23
=1000 gram atoms
Answer:
weight of 1 atom = 6.64×10^-23 g
so, no. of atoms in 40 kg
= 40×10^3 / 6.64×10^-23
= 6.02046 × 10^26 atoms
As, 1 gram atom = no. atoms in one mole = 6.02×10^23 (avagadro number)
so, no. of gram atom
= 6.02046×10^26/6.02×10^23
=1000 gram atoms
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