Chemistry, asked by bossrc64p7l5et, 1 year ago

An atom X has (2,8,6) electrons in its electron shells. It combines with atom Y with 2 electrons in its outermost shell.

1) What type of bond it will be formed ?

2) what is the formula of the compound formed by X and Y ?

Answers

Answered by Anonymous
11
Hey !

Here is your answer !

____________

➡Since there are 6 electrons in outermost shell of X

➡Hence X is a non metal

➡Y has 2 electrons in the outermost shell

➡Hence Y is a metal ✔

➡ Bond formed between a metal and a non metal is --> Ionic bond ✔

✔Hence 1) Ionic bond

2) Formula for its compound is --> YX

How ?✔

Valency of X = 2 ( 8 - 6 = 2 )

Valency of Y = 2

So ✔

YX
_______________


Y will be --> Magnesium ( Mg ) = 2 , 8 , 2

X will be --> Sulphur

Hence compound formed --> MgS
__________________
Hope it helps !

bossrc64p7l5et: Give example by using real atoms
bossrc64p7l5et: I can brainlist your answer
shivanshbhai: plsss do bro
Anonymous: Done
bossrc64p7l5et: Thanks bro
Anonymous: Welcome
Answered by shivanshbhai
1
Ionic bond is formed .
X = sulphur
Y= helium
The compound formed is imagnery because helium gas doesn't reacts as it is a noble gas..

bossrc64p7l5et: Helium is Noble gas. it can't react with other atoms
bossrc64p7l5et: Give a example using real atoms with bond formation
shivanshbhai: Like Mg and O so bond = MgO.
bossrc64p7l5et: O don't have 2 electron in its outermost sheel
bossrc64p7l5et: shell*
bossrc64p7l5et: O have 6 electrons in ots outermost shell
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