Question

An atom x has three electrons more than the noble gas configuration. what type of ion will it form? write the formula of its (i). sulphate, nitrate, phosphate, carbonate, hydroxide.

Answer 1

X has three electrons more than noble gas configuration 
so,it will form X3-         
formula with sulphate is X₂(SO4)₃
nitrate  is X(NO3)₃
phosphate is XPO4
Carbonate is X₂(CO3)₃
hydroxide is  X(OH)₃

Answer 2

Explanation :

According to the question, An atom 'x' has three electrons more than the noble gas configuration. For attaining the stable electronic configuration or noble gas configuration, it will loose 3 extra electrons.

So, it will form a cation (positive ion) and its valency will be, 3.

The valency of the following anion will be,

Valency of Sulphate $(SO_4)$ = 2

Valency of Nitrate $(NO_3)$ = 1

Valency of Phosphate $(PO_4)$ = 3

Valency of Carbonate $(CO_3)$ = 2

Valency of Hydroxide $(OH)$ = 1

Thus, the formula of the compounds will be,

$X_2(SO_4)_3\\\\X(NO_3)_3\\\\X(PO_4)\\\\X_2(CO_3)_3\\\\X(OH)_3$