Question

An attractive force of 5 N is acting between two charges of + 2muC and - 2 mu C placed at some distance. If the charges are mutually touched and placed again at the same distance , what will be the new force, between them ?

Answer 1

$\underline{\boxed{ \huge\purple{ \rm{Answer}}}}$

Given :

$\rm \: Force = 5 \: N \\ \rm \: Q_{1} = 2 \mu{C} \\ \rm \: Q_2 = - 2 \mu{C}$

To Find :

New force between them after touched them.

Formula :

$\rm \: common \: charge \: on \: both \: after \: touched \\ \\ \rm \: \boxed{Q = \frac{Q_{1} + Q_{2}}{2} }$

Calculation :

$\rm \: Q = \frac{2 - 2}{2} = 0 \: \\ \\ \implies \rm \: charge \: on \: both \: is \: now \: zero \\ \\ \therefore \: \orange{ \rm{F = 0}}$