an Audi car is travelling with a speed 180 kmph if the driver applies brakes it decelarates at 10 M per second square find the distance travelled in last and last but one second
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u mean the last one second?...if so the this is the ans.
180kmph= 50m/s
time taken to come to rest:
⇒v=u +at
0=50+(-10)t
t=5 secs
⇒s=ut+1/2at²
⇒s=50×5+1/2×(-10)×5²
s= 125m
so he has travelled 125 m before coming to rest.
so distance travelled in the last second is:
(total distance travelled) - (distance travelled in last 4 secs)
s travelled in the last four secs is:
s=50×4+1/2×(-10)×4²
s=120m
so distance travelled in the last second is:
125-120 = 5m.
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