Question

an auto driver has fixed charge of rupees 50 and then charged rupees 10 per kilometre drawing conversion graph and estimate fare for the ride of 10 kilometre ​

Answer 1

Answer:

x = 0 ; y = 6

x = - 1 ; y = 2

x = - 2 ; y = - 2

Step-by-step explanation:

Solution :-

Let the total distance covered be x km

and, the total fare be Rs. y 

Since, Total fare = fare for the first kilometer + fare for the remaining kilometer of distance  ...........................(1)

We know that the fare for first kilometer is Rs. 10

Fare for the remaining kilometers i.e. (x - 1)

= 4(x - 1)

Put values in (1)

⇒ y = 10(1) + 4(x - 1)

⇒ y = 10 + 4x - 4

⇒ y = 4x + 6

When x = 0, we have, y = 4 × (0) + 6, So, y = 6

When x = - 1, we have, y = 4 × (- 1) + 6, = - 4 + 6

So, y = 2

When x = - 2, we have, y = 4 × (- 2) + 6 = - 8 + 6

So, y = - 2

x = 0 ; y = 6

x = - 1 ; y = 2

x = - 2 ; y = - 2

Now, you can draw the graph easily.

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Answer 2

Answer:

An auto driver has a fixed charged of ₹50 and then charges ₹10 per kilometre . Draw a conversion graph and estimate fare for a ride of 10 km.