Question

An auto driver moving with a speed of 36km/h sees a child standing in the middle of the road. He applies breaks and brings his vehicle to the rest in 5sec, just in time to save the child. With what acceleration will the driver stop the auto.

Answer 1

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u = 36 km/h

v = 0 m/s

t = 5 s

▪Using the first law of motion, the acceleration (a) of the wheeler can be calculated as:

v = u + at

=> a= v- u / t = (0-36)/5 = -7.2 m/s^2

◾The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

I hope, this will help you___❤❤

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Answer 2

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⏬⏬ANSWER⏬⏬


u = 36 km/h

v = 0 m/s

t = 5 s

▪Using the first law of motion, the acceleration (a) of the wheeler can be calculated as:

v = u + at

=> a= v- u / t = (0-36)/5 = -7.2 m/s^2

◾The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

✌I hope, this will help you✌