Physics, asked by m4695241, 6 months ago

an automobile engine develops 100 kw when rotating at 1800 rpm , what force does it deliver ? if the diameter of the flywheel of engine is 1m.

Answers

Answered by chhaviramsharma9564

0

Explanation:

ω=1800 rev/min=

60

1800×2π

rad/s=60π rad/s

Power=100kW=

τ

.

w

⇒100×10

3

=∣

τ

∣ 60π

∣

τ

∣=531Nm

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