Physics, asked by soniamak27, 9 months ago

An automobile engine develops 100H.P. when rotating at a speed of 1800 rad/min. The torque it delivers is
(A) 3.33 W-s
(B) 200W-s
(C) 248.7 W-s
(D) 2487 W-s

Answers

Answered by suhaschandragunemoni
0

D) is the right option I think

Answered by Anonymous
4

\Large\underline{\underline{\sf \orange{Given}:}}

  • Power (P) = 100HP

in Watts 100HP = 74570Watss

  • Speed of rotation \sf{(\omega)} = 1800rpm

1800rpm in rps :-

\implies{\sf \dfrac{2π}{60}×1800 }

\implies{\sf 60π\:rps}

\Large\underline{\underline{\sf \orange{To\:Find}:}}

  • Torque \sf{(\tau)} = ?

\Large\underline{\underline{\sf \orange{Formula\:Used}:}}

\large{\boxed{\sf \red{Power(P)=Torque (\tau).Speed(\omega) }}}

\Large\underline{\underline{\sf \orange{Solution}:}}

\implies{\sf \tau=\dfrac{74570}{60×π} }

\implies{\sf \tau=\dfrac{74570}{188.4}}

\implies{\sf \tau=395.8\:Nm}

\Large\underline{\underline{\sf \orangw{Answer}:}}

⛬ Torque delivers is 395.8Nm

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