Question

An automobile having a mass of 2000 kg cruises at a speed of 20 m/s. If all the wheels are jammed suddenly, how far will the automobile skid before it comes to a halt, assuming that the vehicle doesn't spin or topple. The coefficient of friction between the ground and the tyre is 0.8 [use g = 10 m/s2].​

Answer 1

m=2000 kg

u=20 m/s

v=0

μ=0.8

g=10 m/s^2

therefore acceleration=-μg

=-0.8*10

=-8 m/s^2

we know that

v²-u²=2as

0-400=2*(-8)*s

400/16=s

s=25 m

Hope this helps

(I am also a One Punch Man fan)

Answer 2

The automobile comes to halt at 25 m

Given:

A mass of 2000 kg cruises at a speed of 20 m/s. The coefficient of friction between the ground andthe treee is 0.8

To Find:

When the automobile comes to a halt

Solution:

An automobile having a mass of 2000 kg cruises at a speed of 20 m/s. If all the wheels are jammed suddenly, how far will the automobile skid before it comes to a halt, assuming that the vehicle doesn't spin or topple

To calculate the coefficient of friction using the above question,

At some point when the automobile stops its kinetic energy must be equivalent to the friction loss of energy,

Kinetic energy = Frictional loss of energy

Kinetic energy is equal to the product of Frictional and the length of travel,

We have,

=  Frictional × length of travel

$\frac{1}{2}mv^{2}$ = Ч$mgl$

L =  $\frac{V^{2} }{2 mewg}$

= $\frac{20^2}{2(0.8)(10)}$

= 25m

Using coefficient of friction, the mass of 2000, and a speed of 20 m/s

We get the value as 25m

The automobile comes to a halt at 25 m

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