An automobile moving at 72km/hr reaches the foot of a smooth inclined plane when engine is switched off. How much distance up the inclined plane the automobile goes before coming to rest .The angle of inclination with horizontal is 30°and g=9.8
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12
1/2mv^2=mgh
then h=1000/49,,,
cos30°=d/h
d=2000/49=40.8
then h=1000/49,,,
cos30°=d/h
d=2000/49=40.8
Answered by
7
1/2mv^2 = mgh
Then h= 1000/49
Cos30°=d/h
d=2000/49
d=40.8m
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