An automobile moving at a velocity of 40 km/hr is experiencing a wind resistance of 2kN. If the automobile is moving at a velocity of 50 km/hr, the power required to overcome the wind resistance is
Answers
Answered by
2
Force in both cases will be same as force due to wind will not depend on velocity on the vehicle
Power is F.v = Fv cos(thetha)
As velocity = 50km/h = 50×5/18 = 125/9 m/s
Force = 2000N
Angle between force and velocity = 180° (Obvious)
Power = 2000×125/9 × cos180° = -250000/9 W = -250/9 KW
(-)sign indicates that Power must be in opposite direction of the force due to wind.
43shubhamdubey:
No bro force will not remain same
It is drag force = 0.5*skin drag coefficient*density*velocity^2 *area
It will depend on velocity^2
F1/F2. = V1^2/V2^2 where F1 is 2kN V1 is 40kmph and V2 is 50 kmph . F2 will come out to be 3.125 KN . And power = force *velocity
Power required= 3.125. *,
3.125*50000/3600 = 43.42 kW
Ok got that , Sorry I was wrong
Similar questions