Question

An automobile of 2000Kgm is traveling at a speed of 80 km/h.calculate the amount of heat developed if the automobile comes to rest zooming 50% of the mechanical energy is converted into heat energy.Given J=4.2J/cal​

Answer 1

Free fall in vacuum -

E = mgh = 1 kg * 9.81 m/sec^2 * 500 m = 4,905 Joules/litre

The specific heat of liquid water is -

4,180 Joules/(kg K)

So, this is 4905/4180 = 1.173445 degress C, or K.

Answer 2

$\huge\mathfrak\green{ThankYou!!}$