Question

An automobile starting from rest and travelling in a straight line accelerates from a velocity of 1.5m/s to 5.5m/s in 4 seconds. What is its acceleration and distance travelled ?​

Answer 1

Answer:

The total distance travelled is =625m

Explanation:

The initial velocity is

u

=

0

m

s

−

1

The acceleration is

a

=

10

m

s

−

2

The time is

t

=

5

s

Apply the equation of motion

v

=

u

+

a

t

The velocity is

v

=

0

+

10

⋅

5

=

50

m

s

−

1

The distance travelled in the first

5

s

is

s

=

u

t

+

1

2

a

t

2

=

0

⋅

5

+

1

2

⋅

10

⋅

5

2

=

125

m

The distance travelled in the following

10

s

is

s

1

=

v

t

1

=

50

⋅

10

=

500

m

The total distance travelled is

d

=

s

+

s

1

=

125

+

500

=

625

m

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