An automobile travelling with a speed
of 60 km/h, can brake to stop, within a
distance of 20 m. If the car is going
twice as fast i.e.,
120 km/h, the stopping distance will
be
Answers
Answered by
11
Answer:
answer is 80.15 cm.
Explanation:
Initial velocity U = 60 km/h=16.66m/s
Using V square -U square =2as
given s= 20 m and V=0m/s
=. -(16.66) square=2*a*20
acceleration(a) =6.93 m/s square.
Now in second case :-
U =120 km/ h=33.33m/s and velocity=0 m/s
Using V square -U square= 2as
=-(33.33) square= 2*(-6.93)*s
=s =80.15 cm....
Hope this helps Thank you.......
Answered by
11
answer 80.15 m or 80 m
hope it helps u
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