Question

An automobile travelling with a speed of 60 km/h can broke to stop within a distance 20 m if the car is going twice as fast 120km/h the stopping distance will be

Answer 1

$firstly \: it \: was \: travelling \: with \: speed \: = \: 60km {h}^{ - 1} \\ stop \: within \: a \: distance \: = \: 20m \\ secondly \: it \: was \: travelling \: twice \: the \: first \: speed \: = \: 120km {h}^{ - 1} \\ therefore \: the \: stopping \: distance \: will \: be \: twice \: the \: first \: distance \: = \: (20 \times 2)m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 40m \\ so \: the \: stopping \: distance \: will \: be \: 40m \\ \\ hope \: it \: helps................ \\ plz \: mark \: it \: as \: brainlilest..................$