Question

an automobile travelling with a speed of 60 km per hour can break to stop within a distance of 20 m if the car is going twice as a fast 120 km per hour the stopping distance will be

Answer 1

Hey

Initial Velocity U = 60 km/h = 16.66 m/s 
using V² - U² = 2as 

given s=20 m and V=0 m/s 
=> -(16.66)² = 2*a*20 

=> Acceleration(a)= -6.93 m/s² 

Now in second case U = 120 km/h = 33.33 m/s and V=0 m/s 

using V² - U² = 2as
 
=> -(33.33)² = 2*(-6.93)*s
 
=> s= 80.15 m

i hope its help you
mark brainliest

Answer 2

Answer:

hope it helps you friend