an automobile travelling with a speed of 60 km per hour can break to stop within a distance of 20 m if the car is going twice as a fast 120 km per hour the stopping distance will be
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Hey
Initial Velocity U = 60 km/h = 16.66 m/s
using V² - U² = 2as
given s=20 m and V=0 m/s
=> -(16.66)² = 2*a*20
=> Acceleration(a)= -6.93 m/s²
Now in second case U = 120 km/h = 33.33 m/s and V=0 m/s
using V² - U² = 2as
=> -(33.33)² = 2*(-6.93)*s
=> s= 80.15 m
i hope its help you
mark brainliest
Initial Velocity U = 60 km/h = 16.66 m/s
using V² - U² = 2as
given s=20 m and V=0 m/s
=> -(16.66)² = 2*a*20
=> Acceleration(a)= -6.93 m/s²
Now in second case U = 120 km/h = 33.33 m/s and V=0 m/s
using V² - U² = 2as
=> -(33.33)² = 2*(-6.93)*s
=> s= 80.15 m
i hope its help you
mark brainliest
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