Question

An automobile travelling with a speed of 60 km per hour can break to stop within a distance of 20 m if the car is going twins as fast that is 120 km per hour the stopping distance will be

Answer 1

stopping distance will be 40m

Answer 2

part 1

u=60 kmph
v= 0 kmph
s=20 m= 0.02 km

v^2-u^2=2as

a=-3600/0.04 km/hr^2

a= -90000 km/hr^2

part 2

u=120 km/h
v=0 kmph
a= -90000 km/hr^2

s= v^2-u^2/2a

s=-14400/2*(-90000)

s=14400/180000=0.08 km