An automobile travelling with a speed of 60 km per hour can break to stop within a distance of 20 m if the car is going twins as fast that is 120 km per hour the stopping distance will be
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stopping distance will be 40m
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part 1
u=60 kmph
v= 0 kmph
s=20 m= 0.02 km
v^2-u^2=2as
a=-3600/0.04 km/hr^2
a= -90000 km/hr^2
part 2
u=120 km/h
v=0 kmph
a= -90000 km/hr^2
s= v^2-u^2/2a
s=-14400/2*(-90000)
s=14400/180000=0.08 km
u=60 kmph
v= 0 kmph
s=20 m= 0.02 km
v^2-u^2=2as
a=-3600/0.04 km/hr^2
a= -90000 km/hr^2
part 2
u=120 km/h
v=0 kmph
a= -90000 km/hr^2
s= v^2-u^2/2a
s=-14400/2*(-90000)
s=14400/180000=0.08 km
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