An automobile travelling with a speed of 60km/h can break to stop within a distance of 20m. If a car is going twice as fast, then what is the stopping distance? Answer with full procedure.
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Answer is 20 because 60x2=120 and 20 mx2=40m
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given u1=60km/h
s1=20m
u2=120km/h
distance(S2)=?
we can use this fomULA=(U1/U2)²=S1/S2
=(60/120)²=20/S2
=3600/14400 =20/S2
ON SOLVING 3600/14400 we get 1/4 =20/s2
therefore S2=20×4
=S2= 80m
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