An automobile with a mass of 2000 kg is lifted by a hydraulic cylinder with an area of 0.2 m^2. The pressure in the lifting cylinder is produced by pushing on a 0.008 m^2 cylinder. What force must be exerted on this small cylinder to lift the automobile?
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2x+5=252x=25−52x=20x=202x=10\begin{lgathered}2x + 5 = 25 \\ 2x = 25 - 5 \\ 2x = 20 \\ x = \frac{20}{2} \\ x = 10\end{lgathered}
2x+5=25
2x=25−5
2x=20
x=
2
20
x=10
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