Question

An average induced e.m.f of 0.4V appears in a coil when the current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.4 second.find the coefficient of self induction of the coil.

Answer 1

The coefficient of self induction of the coil is  8×10^−3 H.

Explanation:

Given data:

e = 0.4 V

dI = 10 − (−10) = 20 A

dt = 0.40 s

L=?

Solution:

e = LdI / dt

L = edt / dt = 0.4×0.4 / 20

L = 8×10^−3 H

Hence the coefficient of self induction of the coil is  8×10^−3 H.

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