An axially loaded bar is subjected to a normal stress of 173 mpa. The shear stress in the bar is
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Explanation:
Hey,
We can solve this as below:
=> "Here, An axially loaded bar is subjected to a normal stress of 173 mpa.
So, Normal stress=P=173 MPa
=> To calculate the shear stress in the bar we can use following equation:
=> Shear stress =q=(P/2) sin2θ
Therefore , q= (173/2) = 86.5
=> q=(P/2) sin2θ =86.5*1=86.5 MPa. {sin2*45 = 1}
Thus, The shear stress in the bar is 86.5 MPa"
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