Question

An barrels manufacturer can produce up to 300 barrels per day. The profit made from the

sale of these barrels can be modeled by the function P(x) = -10x2+3500x-66000 where P(x) is

the profit in rupees and x is the number of barrels made and sold.

Based on this model answer the following questions:

(1) When no barrels are produce what is a profit loss?

(a) `22000 (b) `66000

(c) `11000 (d) `33000


(2) What is the bre3ak even point? (Zero profit point is called break even)

(a) 10 barrels (b) 30 barrels

(c) 20 barrels (d) 100 barrels


(3) What is the profit/loss if 175 barrels are produced.

(a) Profit 266200 (b) Loss 266200

(c) Profit 240250 (d) Loss 240250


(4) What is the profit/loss if 400 barrels are produced.

(a) `Profit 266200 (b) `Loss 26600

(c) `Profit 341200 (d) `Loss 342000


(5) What is the maximum prfit which can manufacturer earn?

(a) `240250 (b) `480500

(c) `342000 (d) `342000​

Answer 1

Answer:

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x)=-10x2+3500x-66000 where P(x) is the profit in rupees and x is the number of barrels made and sold.