Question

An car with an initial speed of 4.30 m/s accelerates uniformly at the rate of 3.00
m/s^2.
What is the final speed of the car? ​

Answer 1

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Answer 2

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Ok, so first to solve for the displacement.  You need to know this formula.  Dx = vi(Dt) + 1/2a(Dt)2, where:

            Dx = ???

            vi = 4.30 m/s

            Dt = 5.0 s

            a = 3.0 m/s2

            So, Dx = (4.30 m/s)(5 s) + (1/2)(3.0 m/s2)(5.0 s)2  = 59 m

            Got it?  Good.  Alrighty then, to solve for the speed this is all you need:  vf = vi + a(Dt), vf = ?, vi = 4.30 m/s, a = 3.0 m/s2, Dt = 5.0 s

           . So that's vf = (4.30 m/s) + (3.0 m/s2)(5.0 s) = 19.3 m/s