an converging mirror of focal length 20 cm forms an image which is twice the size of the object. Calculate two possible distances of the object from the mirror
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Given f = - 20 cm h1 = 2h0 where h1 denotes image height and h0 denotes object height
Now m = -v /u = h1/h0
= -v/u = 2h0/h0
= -v/u =2
= v = -2u eq 1
By using mirror formula we have
1/f = 1/v + 1/u
1/-20 = 1/u - 1/2u. ( beacuse v = -2u)
1/-20 = 1/2u
on taking reciprocals both side
-20 = 2u
-10 = u
Putting this value in equation 1
v = - (-20)
v = 20
Hope it will be helpful...
Now m = -v /u = h1/h0
= -v/u = 2h0/h0
= -v/u =2
= v = -2u eq 1
By using mirror formula we have
1/f = 1/v + 1/u
1/-20 = 1/u - 1/2u. ( beacuse v = -2u)
1/-20 = 1/2u
on taking reciprocals both side
-20 = 2u
-10 = u
Putting this value in equation 1
v = - (-20)
v = 20
Hope it will be helpful...
jatindersingh2p6gcb0:
thank you
Answered by
6
hope it helps you to understand the concept
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