An converging mirror of focal length 20cm forms an image which is two times the size of the object. Calculate two possible distances of the object from the mirror.
Answers
Answered by
22
Hi....
1/f = 1/v + 1/u
focal length (f) = -20 cm
v = image distance
u=object distance
now, according to the given question ,
hi / ho = - V/U = 2
hi = 2ho also v = -2u
since we got v = -2u
Thus;
-1/20 = -1/2u + 1/u
-1/20 = -1 + 2 / 2u
-1/20 = 1/2u
2u = - 20
u = -10 cm
Hope this helps u!!
1/f = 1/v + 1/u
focal length (f) = -20 cm
v = image distance
u=object distance
now, according to the given question ,
hi / ho = - V/U = 2
hi = 2ho also v = -2u
since we got v = -2u
Thus;
-1/20 = -1/2u + 1/u
-1/20 = -1 + 2 / 2u
-1/20 = 1/2u
2u = - 20
u = -10 cm
Hope this helps u!!
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Answered by
24
#Ur Ans
__________
mirror formula is
1/f = 1/v + 1/u ---------(1)
where f → focal length = -20 cm
v =>image distance
u=> object distance
now, according to the given question ,
hi / ho = - V/U = 2
⇒ hi = 2ho also v = -2u
since we got v = -2u -----(2)
now by substituting equation (2) in (1) Thus
@⇒ -1/20 = -1/2u + 1/u
@⇒ -1/20 = -1 + 2 / 2u
@⇒ -1/20 = 1/2u
@⇒ 2u = - 20
@⇒ u = -10 cm
Hope it's helpful ✌☺
__________
mirror formula is
1/f = 1/v + 1/u ---------(1)
where f → focal length = -20 cm
v =>image distance
u=> object distance
now, according to the given question ,
hi / ho = - V/U = 2
⇒ hi = 2ho also v = -2u
since we got v = -2u -----(2)
now by substituting equation (2) in (1) Thus
@⇒ -1/20 = -1/2u + 1/u
@⇒ -1/20 = -1 + 2 / 2u
@⇒ -1/20 = 1/2u
@⇒ 2u = - 20
@⇒ u = -10 cm
Hope it's helpful ✌☺
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