Question

An e, a proton and an alpha particle have K.E of 16 E, 4 E
and E respectively. What's the qualitative order of their
Broglie wavelengths?​

Answer 1

Explanation:

An electron, a proton, and an alpha particle have K.E. of 16E, 4E and E respectively. The qualitative order of their de-Broglie wavelengths is λe>p=λa.

The mass of the electron is significantly lower than the mass of proton or alpha particle.

λ= h

h

→λ

e

>λ

p

=λ

α

(since the mass of alpha particles is 4 times the mass of the proton).

Hence, the de-Broglie wavelength of the electron is higher than that of proton or alpha particle.