An e.m.f. 250 microvolt is induced in a coil when current in it changes from 10 ampere to 6 ampere in 0.4 sec. What is the self- inductance of the coil ?
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Given :
emf= 250 micro volt
1volt=10⁶micro volt
250 micro volt= 250/1000000=0.00025V
current changes= 10-6 =4A
time= 0.4s
Self Inductance=L= e / (di/dt)
= 0.00025/ (4) / 0.4
=0.00025x 0.4/4
=0.00025 H
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