Question

An e.m.f of 5volt is produced by a self inductance when the current changes at a steady rate from 3A to 2A in 1 millisecond, The value of self inductance is
1) Zero 2) 5H. 3) 5000H 4)5 mH​

Answer 1

E=5volt

∆I=3-2=1A

t=1×10^-3s

As per the formula,

E= LdI/dt

L=5×10^-3/1

L=5 mH

I hope this helps ( ╹▽╹ )