Question

an earth satellite moves in a circular orbit with tha speed of 6.2 km/s find the time of one revolution and it's centripetal acceleration
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Answer 1

Answer:

Answer

Correct option is

D

175min

v

0

=

r

GM

or r=

v

0

2

GM

and

T=

GM

2πr

3/2

=

v

0

3

2πGM

T=

(6280)

2

×6280×60

2π×6.67×10

−11

×6×10

24

=175min.

Answer 2

Explanation:

An earth satellite moves in a circular orbit with a speed of 6.2km/s. Find the time of one revolution and its centripetal acceleration.