Question

An earth satellite X is revolving around earth in an orbit whose radius is one fourth the radius of orbit of a communication satellite . Time period of revolution of X is

Answer 1

Let r1=r, r2=r/4

According to Kepler's law

(T2/T4)^2 α (r2/r1)^3

(T2/T1)^2 = (r/4*r)^3

T2/T1 = √1/64

T2 =T1/8

T2 = 24/8

=3 hrs

Answer 2

Answer:

3 hrs

Explanation:

see the above attachment.....