Math, asked by bernadethcariaga0, 5 months ago

an earthquake during october 2019 at tulunan cotabato was recorded to have a magnitude of 6.3.Another earthquake somewhere in davao was recorded to have a 7.1 magnitude in December 2018.hiw much more energy was released by 2018 earthquake compared to that of 2019 recorded earthquake?You can refer to the discussion in the introduction to logarithm for computation.​

Answers

Answered by Aera2542
2

Answer:

The 2019 Cotabato earthquakes were an earthquake swarm which struck the province of Cotabato on the island of Mindanao in the Philippines in October 2019. Three of these earthquakes were above 6.0 on the moment magnitude scale with a Mercalli intensity of VIII.

Epicenter: 6°45′N 125°00′E / 6.75°N 125.00°E Coordinates: 6°45′N 125°00′E / ...

Casualties: October 16: 7 dead, 215 injured; October 29 and 31: 24 dead, 11 missing, ...

Max. intensity: VIII (Severe) – MMS; VII (Destructive) – PEIS

Tsunami: None

Answered by HrishikeshSangha
0

15.8 times more energy was released in the earthquake of 2018 compared to the earthquake of 2019.

Given:

The magnitude of Earthquake 1 = 6.3

The magnitude of Earthquake 2 = 7.1

To find:

How much more energy was released in Earthquake 2 compared to 1.

Solution:

The Energy released during an earthquake can be given by the formula

\log E =  1.5*R + 4.8

Where R is the magnitude of the earthquake.

Therefore

\log_{} \frac{E_{2} }{E_{1} } = \log_{} E_{2} - \log_{} E_{1}

\log_{}\frac{E_{2} }{E_{1} }  = 1.5*(7.1-6.3)=1.2

\frac{E_{2} }{E_{1}} = 10^{1.2} = 15.8

Hence the Earthquake in 2018 released 15.8 times the energy the Earthquake of 2019 released.

#SPJ3

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