An easy way to solve this !... a/x- b + a/x-a = 2
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it's not easy... but short I say
a[1/x-b +1/x-a].=2
(x-a+x-b) /(x^2-(a+b)x+ab)=2/a
a(2x-a-b)=2(x^2-(a+b)x+ab)
2x^2-2(a+b-2a)x+(3ab+a^2)=0
Now apply quadratic formula in it
a[1/x-b +1/x-a].=2
(x-a+x-b) /(x^2-(a+b)x+ab)=2/a
a(2x-a-b)=2(x^2-(a+b)x+ab)
2x^2-2(a+b-2a)x+(3ab+a^2)=0
Now apply quadratic formula in it
amrutasaji:
thankyou!!
wlcm
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