Question

an ebonite rod is rubbed with fur and acquire a charge of 8×10^-6 C . calculate the no. of electron transferred.​

Answer 1

Answer:

5×10^13

Explanation:

no. of electrons transferred =total charge/charge of 1 electron

charge of one 1 electron =- 1.6×10^-19

ans=8×10^-6/1.6×10^-19

5×10^13

please mark me the

Answer 2

Answer:

charge acquire by ebonite rod=8×10^-6C

charge of one electron=1.6×10^-19

now,. Q=ne

charge= no. of electron× charge of

1e-

8×10^-6C = n × 1.6 ×10^-19

8×10^-6÷1.6×10^-19 =n

5×10^13 =n

therefore no. of e- is 5×10^13