An echo is returned on 3s.What is the distance of reflecting surface from the source give that the speed of the sound=340m/s
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as you know d=s*t
speed of sound is 340m/s
time taken by sound to reach the reflecting surface=3/2 i.e 1.5 second
so distance = 340*1.5
=510 m
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Speed of sound, v = 342 m s−1
Echo returns in time, t = 3 s
Distance travelled by sound = v × t = 342 × 3 = 1026 m
In the given time interval, sound has to travel a distance that is twice the distance of the reflecting surface and the source.
Hence, the distance of the reflecting surface from the source = (1026/2)m= 513m
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