an echo return 3 sec what is the distances of reflecting surface from the source given that the speed of sound is 342 m sec
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Answered by
3
speed=dis/time
time=3/2=1.5
342 ×1.5 =dis
513 m
time=3/2=1.5
342 ×1.5 =dis
513 m
Answered by
2
T=2d/v
3= 2d/342
342×3/2= d
513m
3= 2d/342
342×3/2= d
513m
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