Physics, asked by shivamsharma31, 11 months ago

An echo returned in 3 s. What is the distance of the reflecting surface from the source, given that the speed of sound is 342 m s−1?

Answers

Answered by singlesitaarat31
6

\red {HELLO\:DEAR}

  1. Speed of sound, v = 342 m s−1
  2. Echo returns in time, t = 3 s
  3. Distance travelled by sound = v × t = 342 × 3 = 1026 m
  4. In the given time interval, sound has to travel a distance that is twice the distance of the reflecting surface and the source.
  5. Hence, the distance of the reflecting surface from the source = (1026/2)m= 513m

\green {VISHU\:PANDAT}

\blue {FOLLOW\:ME}

Answered by ramcharan123456
0

Explanation:

Speed of sound, v = 342 m s−1

Echo returns in time, t = 3 s

Distance travelled by sound = v × t = 342 × 3 = 1026 m

In the given time interval, sound has to travel a distance that is twice the distance of the reflecting surface and the source.

Hence, the distance of the reflecting surface from the source = (1026/2)m= 513m

Similar questions